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# .999 Repeating is Equal to 1

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after 11 votes the winner is...
Sorrow
 Voting Style: Open Point System: 7 Point Started: 3/25/2010 Category: Miscellaneous Updated: 7 years ago Status: Post Voting Period Viewed: 5,514 times Debate No: 11551
Debate Rounds (2)

45 comments have been posted on this debate. Showing 1 through 10 records.
Posted by Torrente 6 years ago
infinity is a concept, not a number =o)D yea baby!!
Posted by Sorrow 7 years ago
Mathematical properties are not physical, you can't see 0.0000000 (ad infinitum) and 1 when applied to anything, that is not impossible either in real life or in math.

My logic is not flawed.
Posted by burnbird14 7 years ago
Even the fraction of a fraction of a fraction of a grain of salt has weight. Maybe not very practical or measurable, but weight nonetheless. Your logic is flawed.
Posted by Sorrow 7 years ago
1 exists as a whole number and a real integer.

0.000 (ad infinitum) ending in a single one, equals 0.
Posted by burnbird14 7 years ago
If .999 repeating is equal to one, then .000...1 must be equal to zero, because when you add them in the real world, they come out to one. However, We know that it cannot equal zero because that 1 exists, making it NOT zero.

What.
Posted by Sorrow 7 years ago
Which, of course, means that all of your arguments are inherently flawed and invalid as they all prove that 0.999_ equals to 1.

I win.
Posted by Sorrow 7 years ago
So if you didn't do anything wrong on paper, yet you essentially modeled the same equation I did, yet you said I could not have subtracted the two values, then your equation must also be meaningless, which begs the question of how it's meaningless mathematically.

The only thing that I can think of of being mathematically meaningless is the real number between 0.999_ and 1, which of course does not exist within any given superset.
Posted by nickthengineer 7 years ago
No.

10x=9.999999

and

x=0.999999

are the same equation. You can't subtract the two. It's meaningless. But on paper, it makes all those repeating 9's go away which is why you like it so much. But it's still meaningless mathematically. Same as this:

x + y = 0
*multiply by 2
2x + 2y = 0
*therefore
x + y = 2x + 2y = 2(x + y)
*therefore
1=2

I didn't do anything wrong on paper but it's mathematically meaningless nonetheless.
Posted by Sorrow 7 years ago
Since this is an equation, we can multiply both sides by 10 and we have
10x=9.9...

We are allowed to subtract the same thing from both sides of an equations.
Since x=.9...
we subtract x from the left side and .9... from the right side. We can do this because they are the same thing. That is how we defined x, in fact. Now we have

10x-x=9.9...-(.9...)
which tells us

x=1

This is because the 1-x-9x=1x and the 9.9...-(.9...)=1
Posted by burnbird14 7 years ago
No need to be rude.
11 votes have been placed for this debate. Showing 1 through 10 records.