1 + 1 is 2
Post Voting Period
The voting period for this debate has ended.
after 3 votes the winner is...
JGHOSTBOY
Voting Style:  Open  Point System:  7 Point  
Started:  8/4/2013  Category:  Miscellaneous  
Updated:  3 years ago  Status:  Post Voting Period  
Viewed:  980 times  Debate No:  36367 
Debate Rounds (2)
Comments (5)
Votes (3)
First round is acceptance only.


I am arguing that 1+1 isn't 2.
I would like to thank my opponent for accepting this debate 1+1 is not 2. This is proven by mathematics when written in binomial base where 1 + 1 is 10 because there is no such number as two in binomial terms. Another case for this is in base 1 formatting. where there is no number 1 so therefore the equation 1 + 1 = 2 doesn't even exist! Through these cases i would like you to vote aff For all proofs, a set of axioms is required to draw justified conclusions. For natural numbers, this framework is called the Peano Axioms: 1. 0 is a natural number. 2. For every natural number x, x = x. 3. For all natural numbers x and y, if x = y, then y = x. 4. For all natural numbers x, y and z, if x = y and y = z, then x = z. 5. For all a and b, if a is a natural number and a = b, then b is also a natural number. 6. For every natural number n, S(n) is a natural number. 7. For every natural number n, S(n) = 0 is false. 8. For all natural numbers m and n, if S(m) = S(n), then m = n. 9. If K is a set such that: 0 is in K, and for every natural number n, if n is in K, then S(n) is in K, then K contains every natural number. In this system, the numbers 1 and 2 are symbols, whose arithmetic form is: S(0) and S(S(0)). Addition is defined inductively, that is: x + 0 = x + S(y) = S(x + y) Thus, 1 + 1 = 1 + S(0) = S(1 + 0) = S(1) Substitute 1 with S(0), S(0) + S(0) = S(S(0) + 0) = S(S(0)) Hence, 1 + 1 = 2 Q.E.D. 
3 votes have been placed for this debate. Showing 1 through 3 records.
Vote Placed by funwiththoughts 3 years ago
PBJS  JGHOSTBOY  Tied  

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Reasons for voting decision: Just because 1+1=10 doesn't mean it isn't 2, and Con did not show that it did.
Vote Placed by JustinAMoffatt 3 years ago
PBJS  JGHOSTBOY  Tied  

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Reasons for voting decision: The resolution was "1+1 is 2"
Pro showed that 1+1 is, in fact, 2.
Con showed that 1+1 could be 10, but not that it isn't 2.
Next time, let's make it more rounds. Clash is the purpose of debate, rather than stating your opinion and hoping more people favor it than your opponent's.
Vote Placed by Ragnar 3 years ago
PBJS  JGHOSTBOY  Tied  

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Reasons for voting decision: Neither side distinguished their argument as better than the other. Pro would have probably won by default, if he had actually refuted anything at all (as opposed to just ignoring it).
(1 + 1)^1 = 1 + 1 = [(1!/0!(10)!)1^1 " 1^0] + [(1!/1!(10)!)1^0 " 1^1] = [1"1"1] + [1"1"1] = 1 + 1 = 2
Please note that zero factorial, denoted as 0!, is equal to 1 and 1^0 is equal to one.
Thus, I could not create a logical rebuttal against PBJS's argument because it was not mathematically valid whatsoever. So, I simply entered my arithmetic proof of 1 + 1 = 2 as my argument.