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The Contender
Con (against)
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# 1 equals 2

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 Voting Style: Open Point System: 7 Point Started: 8/17/2014 Category: Miscellaneous Updated: 3 years ago Status: Post Voting Period Viewed: 972 times Debate No: 60599
Debate Rounds (3)

 Pro I have previously debated that 2=3, and now I will debate that 1=2. First Round is for acceptance. Any questions will be answered in the comments.Report this Argument Con How fun! I was highly amused by your 2=3 debate, so hopefully this one will be good as well :)Report this Argument Pro It shall. I thank my opponent for mustering the courage to accept such an unusual debate, and hope he has a good time. Let's begin, shall we? I will be proving that 1=2. We start with a very basic formula that just about everyone who has done algebra should know: a^2-b^2=(a-b)(a+b) Since variables can be any number, we can safely assume that for this scenario, a=b. That being said, we can replace the "b"s with "a"s. a^2-a^2=(a-a)(a+a) Then, we can simplify the left side of the equation. a(a-a)=(a-a)(a+a) Notice, the two sides have remained equal this entire time. As you can see, both sides of the equation have: (a-a) This means that we can safely remove it, "cancel them out". That leaves us with: a=a+a Which equals: a=2a Then, if you divide both sides by "a", you are left with: 1=2Report this Argument Con Interesting argument, Pro!Pro's method of reaching 1 = 2 can be summarized as follows:The main problem with this can be found in the following portion of that method:In order to reach A = A + A, we have to divide both sides by (A-A) as shown below:But... we then realize that (A - A) = 0By substituting the (A - A)'s in the denominator with zeroes, we get the following:Of course, this is the famous "divide by zero" error (http://www.mathsisfun.com...). It is an 'undefined' operation, and since it is an essential step in Pro's calculation, this renders Pro's method as a whole invalidated, thus negating the resolution.The proper way to simplify this little set-up of Pro's would require going back up to the second step, realizing that both (A-A) and (A^2 - A^2) are equal to zero, and going from there:As of now, Pro has not successfully shown that 1=2. The resolution is negated.Good luck, Pro! Report this Argument Pro You are correct! Congrats! You may now step into the Voting Period and claim your second victory!Report this Argument Con yay! thanks :PReport this Argument
14 comments have been posted on this debate. Showing 1 through 10 records.
Posted by TheRussian 3 years ago
no no, the original does equal out...it's just that after you take the square root, then the two sides are NOT equal....that's why I didn't show it and kinda skipped it like "well, then the -5/2" automatically cancels out" :P
Basically, if you write it out step by step, it will be unequal once you take the square root...
Posted by UchihaMadara 3 years ago
is it that 0.5 =/= -0.5 ?
Posted by TheRussian 3 years ago
Anyway, congrats! :)
Posted by TheRussian 3 years ago
Oh, haha, there's a much simpler problem with it :P
Posted by UchihaMadara 3 years ago
yes, i have haha

the answer is in here: http://www.purplemath.com...
Posted by TheRussian 3 years ago
On a side note, have you managed to figure out my 2=3 problem as well? :P
Posted by Boesball 3 years ago
Con's argument is better, good job con!
Posted by UchihaMadara 3 years ago
i was thinking about making some more arguments along those lines, but i decided that the divide by zero one alone was enough.
Posted by ArcTImes 3 years ago
Con already won with the division by zero problem.
Posted by 9spaceking 3 years ago
con could also make a good case that no number can equal two numbers, and if one equals 0.999....repeating, then one cannot equal 2
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