1 plus 1 equals 2
Debate Rounds (4)
Multiply each side by 2x-3:
Add 3y-3x to both sides:
Factor both sides:
Divide both sides by (x+y-3):
If 1+2 = 3, how could 1+1=3? The only answer to this question is that 1 is interchangible with 2, and this is clearly not the case.
if 1+1=3 and 1+2=3 can't both be true then;
3^0=1 and 4^0=1 can't both be true using your argument.
Just like any number raised to the 0 is 1,
1 plus any number is 3. I can prove this like this;
(-1)-15=(0)-15 You can change the -15 to something else for the rest of the proofs
And, if 3^0=1 and 4^0=1 is correct that your 2nd round argument is invalid.
And how did you get from -1 = 0 to 15 = 0?
I close by saying this: My opponent has not offered a single sound mathematical proof. Any sensible person can see he is wrong.
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