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# Three equals zero

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after 2 votes the winner is...
Lexus
 Voting Style: Open Point System: 7 Point Started: 5/13/2015 Category: Miscellaneous Updated: 2 years ago Status: Post Voting Period Viewed: 1,075 times Debate No: 75254
Debate Rounds (4)

 Pro First round is acceptance.Resolution in words: Three equals zero.Resolution in math: 3 = 0.No semantics. BoP is shared. Report this Argument Con Challenge ACCEPTEDReport this Argument Pro The following is mathematics, followed by the step applied to the number to achieve the next number. This is confusing so I will give you an explanation below.1 = 1 (Multiply by 2)2 = 2 (Add 5)7 = 7 (Multiply by 2)14 = 14The step prior has the equation applied. (This is really hard to explain in words, sorry).1 = 1 (Divide by 3)1/3 = 1/3 (Simplify the right side)1/3 = .33333... (Multiply by three)3/3 = .99999... (Simplify left side)1 = .99999... (Double values present)2(1) = 2(.99999) (Simplify)2 = 1.999...8 (Minus one)1 = .999...8 (Double values present)2 = 1.999...6 (Minus one)1 = .999...6 (Repeat these steps infinitely, where you will theoretically reach a point where 1 = .25)1 = .25 (Double these numbers)2 = .5 (Double again)4 = 1 (Add one)5 = 2 (Double numbers)10 = 4 (Subtract 4 on each side)6 = 0 (Divide by 2)3 = 0.Due to this mathematical proof, I have successfully shown that 3 = 0 in at least one instance.I look forward to my opponent's response. Report this Argument Con 1 = 1 (Divide by 3) 1/3 = 1/3 (Simplify the right side) 1/3 = .33333... (Multiply by three) 3/3 = .99999... (Simplify left side) 1 = .99999... (Double values present) 2(1) = 2(.99999) (Simplify) 2 = 1.999...8 (Minus one) 1 = .999...8 (Double values present) 2 = 1.999...6 (Minus one) 1 = .999...6 (Repeat these steps infinitely, where you will theoretically reach a point where 1 = .25) 1 = .25 (Double these numbers) 2 = .5 (Double again) 4 = 1 (Add one) 5 = 2 (Double numbers) 10 = 4 (Subtract 4 on each side) 6 = 0 (Divide by 2) 3 = 0. "1 = .999...6 (Repeat these steps infinitely, where you will theoretically reach a point where 1 = .25)" Infinitely means never-ending. Thus, you can never conclude that you get 1=.25.Report this Argument Pro My opponent has not met his BoP, and thus automatically loses R2 for lack of any arguments, except for a rebuttal on mine.Now, my opponent does bring up a great point, which is that infinite means never ending. "Infinitely means never-ending. Thus, you can never conclude that you get 1=.25."However, I said that you must perform this step an INFINITE amount of times, or a never-ending amount of times, to get the final answer which is .25. Just because it will not happen in your lifetime, or the lifetime of the universe, does not mean that this possibility does not exist.The possibility is literally 1/∞, or one in an infinite chance.That is not to say, however, that the possibility is EVER 0. It is always existing and thus we must note its existence. Report this Argument Con I would like to support my con argument with an example. A debater has accepted three different debates. He has not finished any nor are any of the debates inactive. How many debates does he still have? The answer is three and not zero. A girl has picked three apples from a tree. How many apples does she have? The answer again is three and not zero. Thus, this 3=0 statement does not have any logic. Math is built upon logic and facts. If 3=0 cannot be supported by logic, then it is known as a False Statement, or a solution that does not fulfill the requirements of an accurate answer.Report this Argument Pro "A debater has accepted three different debates. He has not finished any nor are any of the debates inactive. How many debates does he still have?"Yeah, he has 3. So what? That doesn't dismiss the logic of my argument above, where it was proven mathematically that 3 can equal 0 under special circumstances.I can say that I have 3i (i is sqrt(-1)) debates, how many do I have?Well... I have 0. Not because the math for 3i doesn't exist, but just because it cannot be thought into the physical world."A girl has picked three apples from a tree. How many apples does she have?"AHA, trick question!Perhaps she had apples from before she picked the tree, which would result in a number higher than three."Thus, this 3=0 statement does not have any logic. "The statement has tons of logic. Mathematically, 3 can be equal to 0 in certain conditions, due to the nature of rational numbers and how they are added and whatnot.I already put the response of "I have 3i debates", which is basically that I can have debates in a number system that cannot be thought of into the physical world. That does not mean, however, that 3i does not exist or anything like that."Math is built upon logic and facts. If 3=0 cannot be supported by logic, then it is known as a False Statement"Math is built upon logic and facts, I totally agree.3 = 0 is based upon logic, just cannot be thought of in terms of the physical world.I did not make a false statement, I mathematically proved that 3 = 0. My opponent has made no real arguments that fulfill the BoP that I gave him, he just used physical examples that cannot be reliable enough to have an answer. I used mathematical proof that 3 = 0, whereas my opponent has made baseless claims in a world that cannot fathom true numbers. Vote pro.PS final round is this round. I look forward to your response.Report this Argument Con 1 = 1 (Multiply by 2)2 = 2 (Add 5)7 = 7 (Multiply by 2)14 = 14The step prior has the equation applied. (This is really hard to explain in words, sorry).1 = 1 (Divide by 3)1/3 = 1/3 (Simplify the right side)1/3 = .33333... (Multiply by three)3/3 = .99999... (Simplify left side)1 = .99999... (Double values present)2(1) = 2(.99999) (Simplify)2 = 1.999...8 (Minus one)1 = .999...8 (Double values present)2 = 1.999...6 (Minus one)1 = .999...6 (Repeat these steps infinitely, where you will theoretically reach a point where 1 = .25)1 = .25 (Double these numbers)2 = .5 (Double again)4 = 1 (Add one)5 = 2 (Double numbers)10 = 4 (Subtract 4 on each side)6 = 0 (Divide by 2)3 = 0.In "1 = 1 (Divide by 3)," the number will result in an infinitely repeating value. unless you divide it by itself or multiply it by 0, it is impossible to convert it to a whole number.Thus, the following steps when you supposebly convert it to a whole number, are invalid.Report this Argument
33 comments have been posted on this debate. Showing 1 through 10 records.
Posted by salam.morcos 1 year ago
@daem0n - Good math work. I'm glad you figured it out. Just for fun, do you know that 3=0! :) Here is another way. Let be know if you can find it.

4 = 4
4 - 4 = 4 - 4
since (a^2 - b^2) = (a-b)(a+b)
also (a*b - a*c) = a (b-c)

(2+2)(2-2) = 2 (2-2)

cancel out the right sides

(2+2) = 2

Therefore 4 = 2
2 = 1 (divide by 2)
3 = 2 (add 1 to each side)
1 = 0 (minus 2 to each side)

Since 0 = 1, 1 = 2 and 2 = 3, then 0 = 3.

Enjoy :)
Posted by daem0n 1 year ago
Another way to expand and simplify 2(.99999...) is this:

2(.99999...)
= 2(9/10 + 9/100 + 9/1000 + ...)
= 2(9/10) + 2(9/100) + 2(9/1000) + ...
= 18/10 + 18/100 + 18/1000 + ...
= (10/10 + 8/10) + (10/100 + 8/100) + (10/1000 + 8/1000) + ...
= (1/1 + 8/10) + (1/10 + 8/100) + (1/100 + 8/1000) + ...
= 1/1 + (8/10 + 1/10) + (8/100 + 1/100) + ...
= 1/1 + 9/10 + 9/100 + ...
= 1/1 + (9/10 + 9/100 + ...)
= 1/1 + .99999...
= 1 + 1
= 2
Posted by daem0n 1 year ago
Con needed to identify the fallacy in Pro's attempt at a mathematical proof. Here is how to do that:

Line 5 in Pro"s argument:

1 = .99999...

Good so far. Line 6:

2(1) = 2(.99999)

Pro forgot the ellipsis. Pro should have written "2(1) = 2(.99999...)". But otherwise, good so far.

The derivation Pro uses to turn the right hand side of line 6 into the RHS of line 7:

2(.99999...) = 1.999...8

is incorrect. Pro does not know the meaning of ".99999..." It is shorthand for:

9/10 + 9/100 + 9/1000 + ...

Therefore, two things:

First: "1.999...8" is meaningless. There is no way to translate that shorthand into a sum. (What is 8 supposed to be divided by?) No mathematical proof can be derived from a meaningless statement.

Second, when the expression "2(.99999...)" is validly expanded and simplified, 2 is derived.

2(.99999...)
= 2(9/10 + 9/100 + 9/1000 + ...)
= 2(9/10) + 2(9/100) + 2(9/1000) + ...
= (9/10 + 9/10) + (9/100 + 9/100) + (9/1000 + 9/1000) + ...
= (9/10 + 9/100 + 9/1000 + ...) + (9/10 + 9/100 + 9/1000 + ...)
= .99999... + .99999...
= 1 + 1
= 2

All this tells us is that 2 = 2, which tells us nothing. No mathematical proof can be derived from a statement that tells us nothing.
Posted by tejretics 2 years ago
Poor Con.
Posted by Lexus 2 years ago
@NGEpical simplification does not have to be done to two sides.
I meant simplify the right side into a decimal, not a fraction. This is alowed in mathematics.
Posted by live4ever 2 years ago
@lexus unfortunately that cant be done. Not all numbers have an exact decimal equivalent. Besides you should be able to understand that 0.3333333... isn't an exact third no matter how many recurring 3's there are. why do you think the 3's recur infinitely? Because its not a perfect third. If it were a perfect third the recurring 3's will terminate.
Posted by Lexus 2 years ago
@live4ever please send me a file containing the exact number of 1/3 in decimal. all numbers have a decimal. please send me the one for 1/3. be exact, not approximate
Posted by live4ever 2 years ago
@lexus. the link you sent me has the exact answer of 1/3 and that is 1/3. this is the simplist exact form it can be. The decimal exact equilavelent does not exist but 0.333333... is the closest approximation. That's why the 3's at the end of 0.3333333... goes on infinetly as it keeps getting closer to equaling 1/3 but can never get there.
Posted by NGEpical 2 years ago
"1/3 = 1/3 (Simplify the right side)
1/3 = .33333... (Multiply by three)
3/3 = .99999... (Simplify left side)
1 = .99999... (Double values present)"

This doesn't work, you have to simplify both sides before moving on, you can't simplify one side then do something to both, THEN simplify the other, it doesn't equate.
Posted by Lexus 2 years ago
@live4ever, please send me a file containing the exact value of 1/3, not approximate.
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