The Instigator
james14
Pro (for)
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The Contender
400spartans
Con (against)
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Trigonometry

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Voting Style: Open Point System: 7 Point
Started: 12/10/2014 Category: Miscellaneous
Updated: 2 years ago Status: Post Voting Period
Viewed: 533 times Debate No: 66715
Debate Rounds (3)
Comments (4)
Votes (0)

 

james14

Pro

The tangent of x is equal to the sine of x divided by the cosine of x.

Anyone got a problem with that?

Similarly the cotangent of x is equal to the cosine of x divided by the sine of x.
AND, EVEN MORE AMAZINGLY, sin (90-x) is equal to cos x!!!!!

Can you tell I'm a student who's actually learning something from his schoolwork?

;P

Feel free to debate that too if you like.
400spartans

Con

I accept this, and even though you never specified it, I'll just use this first round for acceptance.

Good luck to my opponent!
Debate Round No. 1
james14

Pro

Okay. Someone accepted.

Now, most trigonometry problems involve a right triangle like so:

triangle 2
Yes. Now, by definition:

sin(θ) = opp÷hyp
cos(θ) = adj÷hyp
tan(θ)= opp÷adj
[1]

Now, what do we get when we devide sin(θ) by cos(θ), substituting?

We get (opp/hyp) divided by (adj/hyp).

In Algebra, we can multiply (or divide) the numerator and denominator of an expression by the same non-zero quantity without changing the value of the expression.

So, if we divide both the top and the bottom by hyp, then we get opp/adj, which is the definition for tan!!

The cotangent is just the inverse of the tangent, which means it is basically .
So instead of being opp/adj it becomes adj/opp. Which, of course, is what we get when we divide cos(x) (adj/hyp) by sin(x) (opp/hyp), because we can eliminate the hypotenuse just as in the tangent's case.

Did I say anthing else? Oh, yeah. Sin(90-θ) = cos(θ).

This is true because:Sin(90-θ) is actually the sine of the other angle in the triangle. I can prove this as this is a right triangle, which has a 90I0; right angle, and every triangle only has 180I0;. Therefore, the other angle must equal (90-θ).

So, instead of taking the value of sin(θ), we're actually taking the value of sin(k), calling k the other angle. Sin(k) would equal, looking back at our diagram, adj/hyp, as θ's adjacent side is k's opposite side.

And of course adj/hyp constitutes cos(θ).

I don't see how you can counter this, Con, but good luck trying!!

[1] http://www.algebralab.org...
400spartans

Con

I can't really use your theta symbol, so I'll just use "x"

1. sin(90-x)=cos(x)

This is where I use the power of...

NON-EUCLIDIAN GEOMETRY!

The most well-known non-euclidian geometry is spherical geometry. It takes place on a sphere.

Here is the triangle which disproves point 1: a triangle who has points on The North Pole, 0"N 0"E, and 0"N 90"E.

This triangle has 3 right angles. From your definition, cos(x) = adj/hyp. Since all three lines are equal (they are all 1/4 the circumference of the Earth), cos(90)=1. However, sin(0) is defined to be 0. If sin(90-x)=cos(x), then 0=1. This is a contradiction, so sin(90-x)=cos(x) is false.

2. sin(x)/cos(x)=tan(x)

Back to our triangle: from it we can determine sin(90)=1 and cos(90) = 1. But, tan(90) is undefined. Since 1/1 doesn't equal undefined (it equals one), sin(x)/cos(x)=tan(x) is false.

3. cos(x)/sin(x)=cot(x)

Using the same reasoning as before, you get 1/1 = 0, which means cos(x)/sin(x)=cot(x) is false.

I hope you have a good response to this, Pro.
Debate Round No. 2
james14

Pro

Goodness.

I was only dealing with plane, Euclidean geometry. I haven't even started the other kind yet.

But Con is quite right. Spherical geometry does work differently.

However, all of my proofs still work, and Con didn't address any of them. Con cannot win just by resorting to equivocation.

Or at least, I'd hope that shouldn't be the case. This is a weird debate.
400spartans

Con

Most of the voters will probably understand that I wouldn't debate pure fact. That wouldn't be debate. However, when things are disagreed upon, I decide to take one side of the debate. I didn't address your arguments because they were fact. Instead I showed a new realm, where conventional rules don't apply.

All you said was, "The tangent of x is equal to the sine of x divided by the cosine of x," and others like that. You didn't address where. I showed that this statement is not true all of the time. This is what is asked of in debates.

In short, I did what is known as winning a debate.

Vote Con!
Debate Round No. 3
4 comments have been posted on this debate. Showing 1 through 4 records.
Posted by Raistlin 2 years ago
Raistlin
Great work con.
Posted by 400spartans 2 years ago
400spartans
I love shocking responses. I just made one right now.
Posted by james14 2 years ago
james14
You'd be surprised.
Posted by TheNamesFizzy 2 years ago
TheNamesFizzy
I'm confused. How would someone debate against fact?
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