Two Plus Two Equals Four
Full resolution: "In elementary level arithmetic, two plus two equals four (2+2=4)."
In honor of the sarcastic one-sided resolution everyone so adores to talk about, I stand to resolve that mathematically, two plus two equals four. Round one is for acceptance.
First and foremost, my opponent was strictly informed that the first round was for acceptance only. Because he presented and argument in the first round, he has violated the rules of this debate. This should, however, only have an effect on the conduct point, and not the argument points. That said, let's continue.
2+2 is both greater than or equal to and less than or equal to 4.
Integers are an infinite group relating to addition. Since 2 is an integer, 2+2 must also be an integer.
Now pretend that 2 + 2 < 4. We have 2 > 0. Adding two to both sides, we get 2+2 > 0+2. Since 0 is the identity element for addition, we have 2 + 2 > 2. So 2<2+2<4. Thus, 2+2 equals three, right?
My opponent has not read the terms of my resolution, as posted in Round one. The resolution is as follows:
"In elementary level arithmetic, two plus two equals four (2+2=4)."
The key term here is "Elementary Level Arithmetic." My opponent argues that 2+2 does not equal 4 in all scales of measurement, which is completely true, and I'm not arguing against that. The only thing I am arguing is that in the math your learn in first grade, 2+2=4.
That said, my opponent has not refuted my mathematical proof in Round 2, which means I win this debate. But if that's not enough, imagine this:
The second successor of zero added to the second successor of zero will equal the fourth successor of zero.
Picture it this way: zero is nothing. We represent nothing with this symbol--- 0.
One more unit than nothing can be known as the successor of zero (or, S(0) or even better, 1.)
Following the pattern, the next unit is S(S(0) or, 2.
Essentially, all that has to be proven is that S(S(0) + S(S(0) = S(S(S(S(0). You don't need to be an expert mathematician that when you take two of the letter "S" and add them to two more of the letter "S", you get four of the letter "S."
In elementary level arithmetic, we express this as 2+2=4.
Because my opponent has disregarded my Round 2 arguments, because his new argument goes outside the terms of my resolution, and through the new reasoning I have presented, you can see that the only reasonable vote is in favor of Pro.
TazM forfeited this round.
Putting the forfeit aside, note that even in the rounds where my opponent didn't forfeit, he has failed to address my arguments throughout this whole debate. Thus, a Pro vote is now fully warranted.
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