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# Two is the same as one.

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 Voting Style: Open Point System: 7 Point Started: 1/7/2008 Category: Science Updated: 9 years ago Status: Voting Period Viewed: 1,268 times Debate No: 1488
Debate Rounds (1)

 Pro Let a = b. Then a^2 = ab. Subtract b^2 from both sides. Then a^2-b^2=ab-b^2. Use difference of squares. (a+b)(a-b)=b(a-b) Divide both sides by (a-b). Then a+b=b. Now let a=1, then b=1. Substitute a=1 and b=1 into a+b=b. Thus 2=1.Report this Argument Con The problem comes with the seventh line: "Divide both sides by (a-b)" It is given that a=b. Thus, we can show by substitution that the second line is equivalent to dividing by (a-a). (a-a) is obviously equal to zero, and division by zero is undefined. Thus, the proof is invalid.Report this Argument
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Posted by ww54ww 9 years ago
WOW! Typo after typo in your argument. Gosh. You should clarify that this proof can be proven correct by utilizing the Mandelbrot Set and graphing a fractal chaos.
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(='.'=)RABBIT POWER!!!
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Posted by solo 9 years ago
Poh-tay-toe, poh-tah-toe... whatever.
Posted by DoubtingThomas 9 years ago
No, my argument wasn't wrong. I made a typo. Sheesh.
Posted by solo 9 years ago
So your argument was wrong? And now you're correcting it in the comments. I see. Nothing hypocritical about doing that, I guess, huh?
Posted by DoubtingThomas 9 years ago
When I said "second line", I meant "seventh", sorry.
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