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Anonymous

# .999...(repeating) =1

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 Voting Style: Open Point System: 7 Point Started: 8/16/2017 Category: Science Updated: 3 years ago Status: Debating Period Viewed: 1,654 times Debate No: 103562
Debate Rounds (4)

32 comments have been posted on this debate. Showing 21 through 30 records.
Posted by Anonymous 3 years ago
I feel dumb that I never took a literal approach to my debate. (And they said autistic people take things literally)
Posted by Anonymous 3 years ago
dividing it into 3 parts and saying those 3 which neither equates to 1 is 3* all togeather,
Posted by Anonymous 3 years ago
Well, I can't say that 0.999 and so on is a one. A small difference is a difference enough. For example, and NDECD cant be a NDCED :3.
Posted by Anonymous 3 years ago
Commondebator, The value still never reaches 1. You're only infinity adding additional decimal places.
Posted by Anonymous 3 years ago
true cant exist without false
Posted by Anonymous 3 years ago
0=nothing=false+truth
1=something=true

at not point does false equal true, they are not the same no matter how you spin it..
Posted by Anonymous 3 years ago
Masterful, with 1.111.... all you need to show is whether .11...=1

so .1111 can be rewritten as

1/10+1/100+1/1000+...

And if we take the sum of this infinite geometric series, then it would be

1/10(1-1/10)
=1/10(9/10)
=1/10(10/9)
=1/9

So in reality, 1.1111.... is actually 1+1/9. Not 1+9/9. Which makes sense since if you divide 1 by 9, you get an infinite number of "1s" on the calculator screen.
Posted by Anonymous 3 years ago
DavitosanX,

Well dx represents an infinitesimally small CHANGE in x of a function. I'm not 100% sure if it applies to an infinite geometric series...
Posted by Anonymous 3 years ago
Of course, for practical purposes 0.999... = 1. If I had two coins and one of them was missing an atom, I wouldn't consider them different.

But for math purposes, I'd go with this. Let x = 0.999... and y = 1. The expression 1/(x-y) evaluates to a very large number that approaches infinity, whereas the expression 1/(x-x) and 1/(y-y) are both divisions by zero, and thus undefined.

Correct me if I'm wrong, but I think the definition of the difference between 1 and 0.999... is actually the differential of calculus, the 'dx'.
Posted by Anonymous 3 years ago
9.9999999999999999999999...*
9.9999999999999999999999...=
99.9999999999999999999999.../
9.9999999999999999999999...=
10
Therefore, 9.999999999999999999999=10
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