## Big Issues

All Big Issues
The Instigator
Pro (for)
Anonymous
Losing
3 Points

Post Voting Period
The voting period for this debate has ended.
after 3 votes the winner is...
Mharman
 Voting Style: Open Point System: 7 Point Started: 3/22/2017 Category: Religion Updated: 3 years ago Status: Post Voting Period Viewed: 683 times Debate No: 101223
Debate Rounds (2)
 Pro and the lier has a lieReport this Argument "truth has advantage and the lier has a lie" Depth analysis: "Truth" and "lie are compound subject nouns, "advantage" and "lie" are direct objects. "and" is a conjunction, and "has" is a linking verb, and "a" is an article adjective. Notice that A is part of the subgroup AA, which is a mathematical impossibility. AA should be the subgroup of A. Notice also that T and L are in the subgroup SN. Now notice that AD, and LEIR are all in the subgroup DO. Notice that DO and SN are a subgroup of N, which is a mathematical impossibility, Since SN should be a part of S, not N. If it were a part of N is would be NS. T and L are one letter groupings, so they should not be subgroups. The same is the case LEIR and AD being a subgroup of DO. Thus, DO should not be a subgroup in the first place. It is also a mathematical impossibility of having two groupings labeled H. Notice how both are a subgroup of LV, which also makes no sense at all. If.. A > AA and AD, in which AA + AC = AD, L > LE > LEI > LEIR, N > NS, S > SN, T =/= L, H^2 = LV, and DO = 0... Then.. L must be a constant doubling variable, since you can keep adding variables on to it. Thus, L = {2, 4, 8, 16, 32,...} This would also mean that T =/= {2, 4, 8, 16, 32,...}. E, I, and R must also be constant doubling variables, since they are part of the equation with L. L must be the smallest one of the four since it comes first, and so on. Notice that the relationship between H and LV. V cannot be 1, H cannot be one, and L cannot be 2 since 1^1=1, not 2. However, it works if H=8, L=4, and V=16, since LV = 64 and 8^2 = 64. Thus... L = 4, H = 8, and V = 16. This also means that E skips the next two numbers in the sequence, and that is the pattern. Thus... E = 32, I = 256, and R = 2,048. If AA + AC = AD, then A = 1, C = 2, and D = 3. Notice how the smaller variables are greater than the multi-digit variables. Thus, they are all negative, but we can cancel them all out. Since D = 3, then O = 0, since 3*0=0. S and N are two variables not in the sequence that still are greater when together than alone. Thus, N = 12 and S = 19, which is also their placing in the alphabet. It is important to note that A is a part of this sequence as well. Notice how T is related to N and S. It is not a factor, but it is related to the number 20. (12*19)/20 = 11.4, thus, with rounding, T =11. Later, the rest of the alphabet fills into the rest of the spots. All the numbers not in the sequences are in the sequence Prev. Value * Fill-in Value = New Value, skipping 13, because having 0 is a chance to get rid of bad luck, and if they interfere with any other sequence, they will be added 1 until there is no conflict. 20 is also skipped due the earlier equation. So, to recap: O = 0 A = 1 C = 2 D = 3 L = 4 H = 8 B = 10 T = 11 N = 12 V = 16 S = 19 E = 32 F = 36 G = 49 J = 90 K = 110 M = 182 P = 240 I = 256 Q = 289 R = 324 U = 441 W = 528 Y = 575 Z = 624 R = 2,048. We get nothing by multiplying these, but we do get something by adding them all together. The alphabet = 5,900. Thett3 has a similar elo. Thett is also a dude pretending to be a girl, which means there is a reverse on what vi_spex said. CONCLUSION: By saying "truth has an evidence advantage", he really means that "lies have have an evidence advantage"! This is however, not true. Vote Con.Report this Argument Pro huhReport this Argument Con has not refuted my points, instead he insists on arguing that lies have evidence advantage. In fact, the truth is that I proved that what he ACTUALLY said of what he really "said", and the evidence is my Round 1 argument. Thus, I win; vote con.Report this Argument  