# Sorry if the question is confusing. Question is in the description.

**Posted by:**Mathgeekjoe

So lets say I have a population of shapes, 70% are quadrilateral. 30% are triangles. Now lets say there are shapes that are regular polygons. 60% of regular polygons are squares. 40% of regular polygons are equilateral triangles. Now here comes the question. Which type of shape is more likely to be a regular polygon?

Quadrilaterals

Triangles

25%
1 votes

75%
3 votes

MGJ... Still working on this? I may mess with this in the morning when my brain is fresh.

A regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

@TBR I trying to figure out how many people take the question differently.

I *am* trying

Wait. Are there two sets of shapes?

I have a population of shapes. 70% are quadrilateral, 30% are triangle.

"Now lets say there are shapes that are regular polygons. 60% of regular polygons are squares. 40% of regular polygons are equilateral triangles." What is the relationship between the regular polygons and the population of shapes?

Some shapes are regular polygons. Some are not.

Do you want us to compare the probability of quadrilateral AND regular and the probability of triangle AND regular, or the probability of regular GIVEN quadrilateral and the probability of regular GIVEN triangle? (Sorry for the clumsy sentences; Maths symbols don't pass through the filter, even after I removed the intersection signs.)

"Which type of shape is more likely to be a regular polygon?"

So forty percent divided by thirty percent is greater than 60percent divided by 70 percent

Diqiucun I disagree. If I had 990 whites and 10 blacks and and 70% of crime was caused by blacks and I had 10 crimes, then I would expect seven of ten of the blacks to have been criminals but only 3 of the 990 whites to be criminals.

So blacks would be more likely to commit crimes

"So blacks would be more likely to commit crimes" Heil can you keep that out of this.

And the thing is is it doesn't matter if 20 or 30 or even 200 crimes were committed as long as the 70/30 ratio is maintained and the 990/10 ratio is maintained blacks will commit more crimes

Oh my bad i inverted the proportions, one group would have to have above 50% for both

Above 50% population and rate

HEIL if you are going to make a statistical point, use triangles and squares, we don't need any political views in this poll.

Fine I won't mentions names of races. If I have 990 of race A and 10 of race B. 8% of crimes were commmitted by race A and 2% committed by race B. For the sake of comparison let's say we have 10 crimes. Then 8 crimes will be from race A and 2 from race B. Eight divided by ninehundred ninety is less than two divided by ten. The thing is this works for all amounts of crime number whether than be 20 or 30 crimes.

Can you keep humans or possible human characteristics out of it. There is a reason WHY I USED SHAPES.

But it doesn't matter whether i use race or shapes, it's the same mathematical concept

It matters because this poll was supposed to be exempt from political biases.

If I have 990 of A and 10 B. 8% of a group of letter is A and 2% of those letters are B. For the sake of comparison let's say we have 10 letters in that group. Then 8 letters will be from A and 2 from B. Eight divided by nine hundred ninety is less than two divided by ten. So that means more percent of B will be that letter group. Happy?

Well you've just had your poll hijacked by a troll.

Besides you kinda need to find a way to incorporate math into real life application

Besides "@TBR I trying to figure out how many people take the question differently." I did as you said to take it differently. I took the question in a racial sense

@heil: You actually made a point. I've just realised I've misread the description...

Hey no changing your answer

"Besides "@TBR I trying to figure out how many people take the question differently." I did as you said to take it differently. I took the question in a racial sense". I meant differently as the difference between the green and red column.

http://pastebin.com/026YxurZ

Heil had me laughing through most of this. That was expert lol

Since it appears the question focuses on how we interpret that last question you posted, I'll guess you meant for use to compare the probability of regular GIVEN quadrilateral and the probability of regular GIVEN triangle. For the proof of why triangle's probability is higher: http://pastebin.com/026YxurZ